silencers

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This topic contains 0 replies, has 1 voice, and was last updated by  JesseVoss 1 week, 5 days ago.

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    JesseVoss
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    • Posts: 15
    Join Date: 05/08/2018

    Hello all,

    Could any body tell me why the number of holes on a silencer should be at least 30% of the surface area
    and the diameter of holes 4-6 mm,is there any formula in this case,I know these are Helmholz resonators
    but I have not come across any particular formula which gives delta=function (d,n),delta being the
    noise reduction and d the diameter of holes and n number of holes per unit area of the silencer?

    Please help.

    I did not find the right solution from the internet.

    References:-
    http://forum.studiotips.com/viewtopic.php?f=1&t=3372
    Creative marketing service

    Thanks

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